From the bash man page:
${parameter##word}
Remove matching prefix pattern. The word is expanded to produce
a pattern just as in pathname expansion. If the pattern matches
the beginning of the value of parameter, then the result of the
expansion is the expanded value of parameter with the shortest
matching pattern (the ``#'' case) or the longest matching patâ
tern (the ``##'' case) deleted. If parameter is @ or *, the
pattern removal operation is applied to each positional parameâ
ter in turn, and the expansion is the resultant list. If paramâ
eter is an array variable subscripted with @ or *, the pattern
removal operation is applied to each member of the array in
turn, and the expansion is the resultant list.
${parameter%%word}
Remove matching suffix pattern. The word is expanded to produce
a pattern just as in pathname expansion. If the pattern matches
a trailing portion of the expanded value of parameter, then the
result of the expansion is the expanded value of parameter with
the shortest matching pattern (the ``%'' case) or the longest
matching pattern (the ``%%'' case) deleted. If parameter is @
or *, the pattern removal operation is applied to each posiâ
tional parameter in turn, and the expansion is the resultant
list. If parameter is an array variable subscripted with @ or
*, the pattern removal operation is applied to each member of
the array in turn, and the expansion is the resultant list.
So in conclusion, with your example in mind, param=${param## }; will remove the leading space from the variable param and ${parameter%%word} will remove the trailing space
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