Do you want mathematical proof?
(1) k(i - 1) = f(i)
(2) j = i - 1
from (1) & (2):
(3) k(j) = f(i)
from (2):
(4) i = j + 1
from (3) & (4)
(5) k(j) = f(j + 1)
q.e.d.
Of course (fun v -> k(v+1))
is your k
and the inside k
is f
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