I believe this solution should now give you the desired result:
# We are going to assign a new column
df = df.assign(
# based on a function that we will apply
new_column=df.apply(
# If our row index is not 0: --> if row.name !=0
# we take the value of column["b"] --> row["b]
# we add the value located at the current row index -1 --> df["b"].iat[row.name -1]
# then we divide by 3 without rest --> //3
lambda row: (row["b"] + df["b"].iat[row.name - 1])//3 if row.name != 0 else "", axis=1
)
)
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